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Answer: b
Explanation: F = q1q2/(4∏εor2) = -2 X 9/(10-9 X 12) = -18 X 109.
To find the force between two charges, we can use Coulomb’s law, which is given by the formula:
[
F = k frac{|q_1 q_2|}{r^2}
]
Where:
– (F) is the force between the charges,
– (k) is Coulomb’s constant ((8.99 times 10^9 , text{N m}^2/text{C}^2)),
– (q_1) and (q_2) are the amounts of the charges,
– (r) is the distance separating the charges.
Given:
– (q_1 = 2 , text{C}),
– (q_2 = -1 , text{C}),
– (r = 1 , text{m}).
Substituting these values into the formula:
[
F = 8.99 times 10^9 frac{|2 times (-1)|}{1^2}
]
[
F = 8.99 times 10^9 frac{2}{1}
]
[
F = 8.99 times 10^9 times 2
]
[
F = 17.98 times 10^9 , text{N}
]
Since the charges have opposite signs, the force will be attractive.
Therefore