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Answer: b
Explanation: The force on a conductor is given by F = BIL, where B = 20, I = 0.5 and L =12. Force F = 20 X 0.5 x 12 = 120 N
To find the force on the conductor, we can use the equation of the magnetic force on a current-carrying conductor, which is given by:
[ F = BIL sin(theta) ]
Where:
– (F) is the force in newtons (N)
– (B) is the magnetic flux density in teslas (T) (in your case, “units” need to be understood as teslas for the equation to make sense, even though “20 units” is not standard SI notation)
– (I) is the current in amperes (A)
– (L) is the length of the conductor in meters (m)
– (theta) is the angle between the direction of the magnetic field and the current in the conductor. Since this angle is not specified, if we assume it to be 90 degrees ((sin(90^circ) = 1) for maximum force), the formula simplifies to (F = BIL).
Given:
– (B = 20) T (assuming the units mentioned are teslas)
– (L = 12) m
– (I = 0.5) A
Substituting these values into the equation:
[ F = 20 times 0.5 times 12 ]
[ F = 10 times 12 ]
[ F = 120 ] N
Therefore, the force on the conductor is 120 newtons.