jangyasinniTeacher
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d) 4
Explanation: Jd = dD/dt = εdE/dt in time domain. For frequency domain, convert using
Fourier transform, Jd = εjωE. The magnitude of
Jd = εωE = ε(2πf)E. On substituting, we get 4 ampere.
d
Explanation: Jd = dD/dt = εdE/dt in time domain. For frequency domain, convert using
Fourier transform, Jd = εjωE. The magnitude of
Jd = εωE = ε(2πf)E. On substituting, we get 4 ampere.
To find the magnitude of the displacement current density ((J_d)) in air for a given frequency, you use the relation for displacement current density in the frequency domain, which is given by the formula
[ J_d = jomegaepsilon E ]
Where:
– (J_d) is the displacement current density.
– (j) represents the imaginary unit (sqrt(-1)).
– (omega) is the angular frequency, obtained from (2pi f), with (f) being the frequency in hertz.
– (epsilon) is the permittivity of the medium (for air, it’s close to the permittivity of free space (epsilon_0 = 8.854 times 10^{-12} F/m)).
– (E) is the magnitude of the electric field.
Given:
– Frequency, (f = 18 , GHz = 18 times 10^9 , Hz)
– Electric field, (E = 4) units.
First, calculate (omega):
[ omega = 2pi f = 2pi times 18 times 10^9 ]
[ omega approx 113.1 times 10^9 , rad/s ]
Now, substitute (omega), (E), and (epsilon_0) into the (J_d) formula:
[ J_d = jomega