Latching current for an SCR is 100 mA, DC source of 200 V is also connected from the SCR to the L load. Compute the minimum width of the gate pulse required to turn on the device. Take L = 0.2 H

To calculate the minimum width of the gate pulse required to turn on the SCR, we can use the formula that relates the latching current (I_L), the inductance (L), and the applied voltage (V) to find the energy required to turn on the device.

1. The latching current (I_L) is given as 100 mA or 0.1 A.
2. The inductance (L) is given as 0.2 H.
3. The applied voltage (V) is 200 V.

To find the minimum width of the gate pulse (t), we first need to compute the time constant of the inductor using the formula:

[

V = L frac{dI}{dt}

]

Rearranging the formula gives us:

[

dt = frac{L}{V} dI

]

Now, we integrate it from 0 to (I_L) (0 to 0.1 A):

[

t = int_0^{I_L} frac{L}{V} dI = frac{L}{V} I_L

]

Substituting the known values:

[

t = frac{0.2 , text{H}}{200 , text{V}} cdot 0.1 , text{A}

]

[

t = frac{0.2}{200} cd