Poll Results
No votes. Be the first one to vote.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
No votes. Be the first one to vote.
False
a
Explanation: In a dielectric-dielectric boundary, if a free surface charge density exists at
the interface, then the normal components of the electric flux density are discontinuous
at the boundary, which means Dn1 = Dn2