Two six pulse converters used for bipolar HVDC transmission system, are rated at 1000 MW, +- 200 kV. Find the dc current in the transmission line.

To find the DC current in the transmission line for a bipolar HVDC (High Voltage Direct Current) transmission system with the given ratings, we can use the formula:

[

P = V times I

]

Where:

– ( P ) is the power in watts (W)

– ( V ) is the voltage in volts (V)

– ( I ) is the current in amperes (A)

Since the system is rated at 1000 MW (which is ( 1000 times 10^6 ) W) and ±200 kV (which translates to 200,000 V), we will use the absolute value for voltage, and remember that since it is a bipolar system, the total voltage across the line would be 400,000 V (200 kV per pole).

Thus, the current can be calculated as follows:

[

I = frac{P}{V}

]

Substituting the values:

[

I = frac{1000 times 10^6}{400,000}

]

Calculating this gives:

[

I = frac{1000 times 10^6}{400,000} = 2500 text{ A}

]

Therefore, the DC current in the transmission line is 2500 A.