Poll Results
No votes. Be the first one to vote.
Participate in Poll, Choose Your Answer.
What is the formula of the inner cylindrical heat dissipating surface?
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
The formula you’re looking for, which pertains to the calculation of the surface area of an inner cylinder (often relevant in heat dissipation contexts, such as in heat exchangers or cooling systems for electronics or machinery) depends fundamentally on the geometry of the cylinder. Specifically, if you’re interested in calculating the surface area of the internal face of a cylindrical object, which is critical for understanding heat dissipation rates (as surface area directly impacts the ability of the object to dissipate heat), you can use the following formula:
[ text{Surface Area} = 2pi rh ]
Where:
– ( r ) is the inner radius of the cylinder (the distance from the center of the cylinder to its inner surface).
– ( h ) is the height of the cylinder.
– ( pi ) (Pi) is a mathematical constant, approximately equal to 3.14159.
This formula calculates the lateral surface area of the inner side of a cylindrical tube, assuming it’s open at both ends. If you’re dealing with a closed cylinder and need to include the area of the two bases in your calculation for complete internal surface area, you’d add the area of both circles (each with an area of ( pi r^2 )) to the lateral area, giving you:
[ text{Total Inner Surface Area} = 2pi rh + 2pi r^2 ]
This second formula provides the total internal surface area of
b
Explanation: The length of mean turn is first calculated. Next, the axial length of coil is
calculated and on substitution gives the inner cylindrical heat dissipating surface.