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Answer: b
Explanation: The electric flux density of a field is the sum of εE and polarisation P. It
gives D = εE + P. When electric field becomes zero, it is clear that D = P.
When the electric field becomes zero, the following relation holds good:
### 1. The net charge enclosed by a Gaussian surface is zero.
This statement is based on Gauss’s Law, which relates the electric flux through a closed surface to the charge enclosed by that surface. Specifically, Gauss’s Law can be expressed as:
[ Phi_E = frac{Q_{text{enc}}}{varepsilon_0} ]
Here, (Phi_E) is the electric flux through a Gaussian surface, (Q_{text{enc}}) is the net charge enclosed by the surface, and (varepsilon_0) is the permittivity of free space. When the electric field ((E)) is zero everywhere on the surface, the electric flux is also zero, which implies that (Q_{text{enc}} = 0).
### 2. The potential difference between any two points is zero.
In a region where the electric field is zero, the potential difference ((V)) between any two points is also zero. This can be seen from the relationship between the electric field and the electric potential difference, given by:
[ V = – int vec{E} cdot dvec{l} ]
Here, (V) is the potential difference, (vec{E}) is the electric field vector, and (dvec{l}) is a small displacement vector along the path over