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jangyasinni

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  1. Asked: August 29, 2024In: Education

    Poisson equation can be derived from which of the following equations?

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 29, 2024 at 12:35 am

    a Explanation: The point of Gauss law is given by, Div (D)= ρv. On putting D= ε E and E=- Grad (V) in Gauss law, we get Del 2 (V)= -ρ/ε, which is the Poisson equation.

    a

    Explanation: The point of Gauss law is given by, Div (D)= ρv. On putting

    D= ε E and E=- Grad (V) in Gauss law, we get Del

    2

    (V)= -ρ/ε, which is the Poisson

    equation.

    See less
      • 0
  2. Asked: August 29, 2024In: Education

    The function V = e x sin y + z does not satisfy Laplace equation. State True/False.

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 29, 2024 at 12:31 am

    b Explanation: Grad (V) = e x sin y i + e x cos y j + k. Div(Grad(V)) = e x sin y – e x sin y + 0= 0.Thus Laplacian equation Div(Grad(V)) = 0 is true.

    b

    Explanation: Grad (V) = e

    x

    sin y i + e

    x cos y j + k. Div(Grad(V)) = e

    x

    sin y – e

    x

    sin y + 0=

    0.Thus Laplacian equation Div(Grad(V)) = 0 is true.

    See less
      • 0
  3. Asked: August 28, 2024In: Education

    Calculate the charge density when a potential function x 2 + y 2 + z 2 is in air(in 10-9 order

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 11:23 pm

    a Explanation: The Poisson equation is given by Del 2 (V) = -ρ/ε. To find ρ, put ε = 8.854 x 10 -12 in air and Laplacian of the function is 2 + 2 + 2 = 6. Ρ = 6 x 10 -9 /36π = 1/6π units.

    a

    Explanation: The Poisson equation is given by Del

    2

    (V) = -ρ/ε. To find ρ, put ε = 8.854 x

    10

    -12 in air and Laplacian of the function is 2 + 2 + 2 = 6. Ρ = 6 x 10

    -9

    /36π = 1/6π units.

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      • 0
  4. Asked: August 28, 2024In: Education

    Suppose the potential function is a step function. The equation that gets satisfied is

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 11:22 pm

    a Explanation: Step is a constant function. The Laplace equation Div(Grad(step)) will become zero. This is because gradient of a constant is zero and divergence of zero vector will be zero.

    a

    Explanation: Step is a constant function. The Laplace equation Div(Grad(step)) will

    become zero. This is because gradient of a constant is zero and divergence of zero

    vector will be zero.

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      • 0
  5. Asked: August 28, 2024In: Education

    If Laplace equation satisfies, then which of the following statements will be true?

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 11:21 pm

    b Explanation: Laplace equation satisfying implies the potential is not necessarily zero due to subsequent gradient and divergence operations following. Finally, if potential is assumed to be zero, then resistance is zero and current will be infinite.

    b

    Explanation: Laplace equation satisfying implies the potential is not necessarily zero due

    to subsequent gradient and divergence operations following. Finally, if potential is

    assumed to be zero, then resistance is zero and current will be infinite.

    See less
      • 0
  6. Asked: August 28, 2024In: Education

    In free space, the Poisson equation becomes

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 11:20 pm

    c Explanation: The Poisson equation is given by Del 2 (V) = -ρ/ε. In free space, the charges will be zero. Thus the equation becomes, Del 2 (V) = 0, which is the Laplace equation

    c

    Explanation: The Poisson equation is given by Del

    2

    (V) = -ρ/ε. In free space, the charges

    will be zero. Thus the equation becomes, Del

    2

    (V) = 0, which is the Laplace equation

    See less
      • 0
  7. Asked: August 28, 2024In: Education

    The given equation satisfies the Laplace equation. V = x 2 + y 2 – z 2 . State True/False.

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 11:19 pm

    a Explanation: Grad (V) = 2xi + 2yj – 4zk. Div (Grad (V)) = Del 2 (V) = 2+2-4 = 0. It satisfies the Laplacian equation. Thus the statement is true

    a

    Explanation: Grad (V) = 2xi + 2yj – 4zk. Div (Grad (V)) = Del

    2

    (V) = 2+2-4 = 0. It satisfies

    the Laplacian equation. Thus the statement is true

    See less
      • 0
  8. Asked: August 28, 2024In: Education

    Find the permittivity of the surface when a wave incident at an angle 60 is reflected by the surface at 45 in air.

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 11:16 pm

    d Explanation: From the relations of the boundary conditions of a dielectric-dielectric interface, we get tan θ1/tan θ2 = ε1/ε2. Thus tan 60/tan 45 = ε1/1. We get ε1 = tan 60 = 1.73

    d

    Explanation: From the relations of the boundary conditions of a dielectric-dielectric

    interface, we get tan θ1/tan θ2 = ε1/ε2. Thus tan 60/tan 45 = ε1/1. We get ε1 = tan 60 =

    1.73

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      • 0
  9. Asked: August 28, 2024In: Education

    A wave incident on a surface at an angle 60 degree is having field intensity of 6 units. The reflected wave is at an angle of 30 degree. Find the field intensity after reflection.

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 11:15 pm

    c Explanation: By Snell’s law, the relation between incident and reflected waves is given by, E1 sin θ1 = E2 sin θ2. Thus 6 sin 60 = E2 sin 30. We get E2 = 6 x 1.732 = 10.4 units.

    c

    Explanation: By Snell’s law, the relation between incident and reflected waves is given

    by, E1 sin θ1 = E2 sin θ2. Thus 6 sin 60 = E2 sin 30. We get E2 = 6 x 1.732 = 10.4 units.

    See less
      • 0
  10. Asked: August 28, 2024In: Education

    The electric field intensity of a surface with permittivity 3.5 is given by 18 units. What the field intensity of the surface in air?

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 11:14 pm

    c Explanation: The relation between flux density and permittivity is given by En1/En2 = ε2/ ε1. Put En1 = 18, ε1 = 3.5 and ε2 = 1. We get En2 = 18 x 3.5 = 63 units.

    c

    Explanation: The relation between flux density and permittivity is given by En1/En2 = ε2/

    ε1. Put En1 = 18, ε1 = 3.5 and ε2 = 1. We get En2 = 18 x 3.5 = 63 units.

    See less
      • 0
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