jangyasinniTeacher

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To find the field intensity of a reflected wave, one would typically need to know the specific details about the surface material, the type of wave (electromagnetic, sound, etc.), and any relevant boundary conditions or material properties (such as impedance, reflectivity, absorption coefficients, etc.). The angles of incidence and reflection alone, along with the initial intensity, do not provide enough information to directly calculate the intensity of the reflected wave without additional context or assumptions about the nature of the wave and the surface.

In the case of electromagnetic waves, for instance, the reflectivity of a surface and the change in intensity would also depend on the polarization of the wave relative to the plane of incidence. For non-electromagnetic waves, like sound waves, other factors such as the impedance mismatch between the media would play a crucial role.

Given just the angles of incidence (60 degrees) and reflection (30 degrees) and the initial field intensity (6 units), and without specifying the type of wave or properties of the medium or surface, it’s not possible to calculate the field intensity of the reflected wave precisely. Additional specific details about the scenario are needed.

c

Explanation: By Snell’s law, the relation between incident and reflected waves is given

by, E1 sin θ1 = E2 sin θ2. Thus 6 sin 60 = E2 sin 30. We get E2 = 6 x 1.732 = 10.4 units.

c

Explanation: By Snell’s law, the relation between incident and reflected waves is given

by, E1 sin θ1 = E2 sin θ2. Thus 6 sin 60 = E2 sin 30. We get E2 = 6 x 1.732 = 10.4 units.