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jangyasinni

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  1. Asked: August 28, 2024In: Education

    Find the mobility of the electrons when the drift velocity is 23 units and the electric field is 11 units.

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 10:39 pm

    b Explanation: The mobility is defined as the drift velocity per unit electric field. Thus μe = vd/E = 23/11 = 2.1 units.

    b

    Explanation: The mobility is defined as the drift velocity per unit electric field. Thus μe =

    vd/E = 23/11 = 2.1 units.

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      • 0
  2. Asked: August 28, 2024In: Education

    Find the electron density when convection current density is 120 units and the velocity is 5m/s

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 10:29 pm

    c Explanation: The convection current density is given by J = ρe x v. To get ρe, put J = 120 and v = 5. ρe = 120/5 = 24 units

    c

    Explanation: The convection current density is given by J = ρe x v. To get ρe, put J =

    120 and v = 5. ρe = 120/5 = 24 units

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      • 0
  3. Asked: August 28, 2024In: Education

    Compute the conductivity when the current density is 12 units and the electric field is 20 units. Also identify the nature of the material.

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 10:28 pm

    c Explanation: The current density is the product of conductivity and electric field intensity. J = σE. To get σ, put J = 12 and E = 20. σ = 12/20 = 0.6. Since the conductivity is less than unity, the material is a dielectric.

    c

    Explanation: The current density is the product of conductivity and electric field intensity.

    J = σE. To get σ, put J = 12 and E = 20. σ = 12/20 = 0.6. Since the conductivity is less

    than unity, the material is a dielectric.

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      • 0
  4. Asked: August 28, 2024In: Education

    Calculate the charge density for the current density given 20sin x i + ycos z j at the origin

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 10:27 pm

    b Explanation: Using continuity equation, the problem can be solved. Div(J) = – dρ/dt. Div(J) = 20cos x + cos z. At origin, we get 20cos 0 + cos 0 = 21. To get ρ, on integrating the Div(J) with respect to t, the charge density will be 21t

    b

    Explanation: Using continuity equation, the problem can be solved. Div(J) =

    – dρ/dt. Div(J) = 20cos x + cos z. At origin, we get 20cos 0 + cos 0 = 21. To get ρ, on

    integrating the Div(J) with respect to t, the charge density will be 21t

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      • 0
  5. Asked: August 28, 2024In: Education

    The continuity equation is a combination of which of the two laws?

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 10:26 pm

    b Explanation: I = ∫ J.ds is the integral form of Ohm’s law and Div (J) = dq/dt is the Gauss law analogous to D. Through these two equations, we get Div(J) = -dρ/dt. This is the continuity equation.

    b

    Explanation: I = ∫ J.ds is the integral form of Ohm’s law and Div (J) = dq/dt is the Gauss

    law analogous to D. Through these two equations, we get Div(J) = -dρ/dt. This is the

    continuity equation.

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      • 0
  6. Asked: August 28, 2024In: Education

    Find the current when the charge is a time function given by q(t) = 3t + t 2 at 2 seconds.

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 10:24 pm

    c Explanation: The current is defined as the rate of change of charge in a circuit ie, I = dq/dt. On differentiating the charge with respect to time, we get 3 + 2t. At time t = 2s, I = 7A

    c

    Explanation: The current is defined as the rate of change of charge in a circuit ie, I =

    dq/dt. On differentiating the charge with respect to time, we get 3 + 2t. At time t = 2s, I =

    7A

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      • 0
  7. Asked: August 28, 2024In: Education

    Compute the loss factor when the loss tangent is 0.88 and the real part of dielectric is 24.

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 10:23 pm

    d Explanation: The loss factor is nothing but the imaginary part of AC dielectric. It is given by, ε“ = ε` tan δ. We get loss factor as 24 x 0.88 = 21.12.

    d

    Explanation: The loss factor is nothing but the imaginary part of AC dielectric. It is given

    by, ε“ = ε` tan δ. We get loss factor as 24 x 0.88 = 21.12.

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      • 0
  8. Asked: August 28, 2024In: Education

    Choose the best definition of dielectric loss

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 10:22 pm

    a Explanation: In the scenario of an AC field, the absorption of electrical energy by a dielectric material is called as dielectric loss. This will result in dissipation of energy in the form of heat.

    a

    Explanation: In the scenario of an AC field, the absorption of electrical energy by a

    dielectric material is called as dielectric loss. This will result in dissipation of energy in

    the form of heat.

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  9. Asked: August 28, 2024In: Education

    When a dielectric loses its dielectric property, the phenomenon is called

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 10:21 pm

    b Explanation: Due to various treatments performed on the dielectric, in order to make it conduct, the dielectric reaches a state, where it loses its dielectric property and starts to conduct. This phenomenon is called as dielectric breakdown.

    b

    Explanation: Due to various treatments performed on the dielectric, in order to make it

    conduct, the dielectric reaches a state, where it loses its dielectric property and starts to

    conduct. This phenomenon is called as dielectric breakdown.

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      • 0
  10. Asked: August 28, 2024In: Education

    Calculate the loss tangent when the dielectric constant in AC field is given by 3 + 2j.

    jangyasinni
    jangyasinni Teacher
    Added an answer on August 28, 2024 at 10:19 pm

    d Explanation: The AC dielectric constant is given by εr = ε` – jε“, where ε` is the real part of AC dielectric and ε“ is the imaginary part of AC dielectric. The loss tangent is given by tan δ = ε“/ε` = -2/3.

    d

    Explanation: The AC dielectric constant is given by εr = ε` – jε“, where ε` is the real part

    of AC dielectric and ε“ is the imaginary part of AC dielectric. The loss tangent is given by

    tan δ = ε“/ε` = -2/3.

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      • 0
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