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The expression for the inductance in terms of turns, flux and current is given by
a Explanation: We know that e = -N dφ/dt and also e = -L di/dt. On equating both we get, L = Ndφ/di is the expression for inductance.
a
See lessExplanation: We know that e = -N dφ/dt and also e = -L di/dt. On equating both we get, L = Ndφ/di is the expression for inductance.
The equivalent inductances of two coils 2H and 5H in series aiding flux with mutual inductance of 3H is
d Explanation: The equivalent inductance of two coils in series is given by L = L1 + L2 + 2M, where L1 and L2 are the self inductances and M is the mutual inductance. Thus L =2 + 5 + 2(3) = 13H.
d
See lessExplanation: The equivalent inductance of two coils in series is given by L = L1 + L2 +
2M, where L1 and L2 are the self inductances and M is the mutual inductance. Thus L =2 + 5 + 2(3) = 13H.
Calculate the emf of a coil with turns 100 and flux rate 5 units.
d Explanation: The emf is the product of the turns of the coil and the flux rate. Thus e = -N dφ/dt, where the negative sign indicates that the emf induced is opposing the flux. Thus e = -100 x 5 = -500 units.
d
See lessExplanation: The emf is the product of the turns of the coil and the flux rate. Thus e = -N dφ/dt, where the negative sign indicates that the emf induced is opposing the flux. Thus e = -100 x 5 = -500 units.
A boundary of separation between two magnetic materials is identified by which factor?
a Explanation: Two materials are differentiated by their permeability in case of magnetic and permittivity in case of electric. Thus at the boundary of separation, change in permeability is identified for magnetic materials.
a
See lessExplanation: Two materials are differentiated by their permeability in case of magnetic and permittivity in case of electric. Thus at the boundary of separation, change in permeability is identified for magnetic materials.
Find the magnetic moment of a material with magnetization 5 units in a volume of 35 units.
d Explanation: The magnetization is the ratio of the magnetic moment and the volume. To get moment, put M = 5 and V = 35, thus moment will be 5 x 35 = 175 units.
d
See lessExplanation: The magnetization is the ratio of the magnetic moment and the volume. To get moment, put M = 5 and V = 35, thus moment will be 5 x 35 = 175 units.
Find the ratio of permeability of the two media when the wave is incident on the boundary at 45 degree and reflected by the boundary at 60 degree.
c Explanation: From the magnetic boundary conditions, the ratio of permeability μ1/μ2 =tan θ1/tan θ2 and θ1 = 45, θ2 = 60. Thus we get μ1/μ2 = 1/√3. The ratio will be 1:√3.
c
See lessExplanation: From the magnetic boundary conditions, the ratio of permeability μ1/μ2 =tan θ1/tan θ2 and θ1 = 45, θ2 = 60. Thus we get μ1/μ2 = 1/√3. The ratio will be 1:√3.
Find the magnetization of the material with susceptibility of 6 units and magnetic field intensity of 13 units.
c Explanation: The magnetization is the product of the susceptibility and the magnetic field intensity. Thus M = 6 x 13 = 78 units.
c
See lessExplanation: The magnetization is the product of the susceptibility and the magnetic field intensity. Thus M = 6 x 13 = 78 units.
The line integral of the magnetic field intensity is the
b Explanation: The line integral of the magnetic field intensity is given by ∫H.dl. This is same as the current component. From this relation, the Ampere law can be deduced.
b
See lessExplanation: The line integral of the magnetic field intensity is given by ∫H.dl. This is
same as the current component. From this relation, the Ampere law can be deduced.
The normal component of magnetic field intensity at the boundary of separation of the medium will be
a Explanation: The normal component and tangential components of the magnetic flux density will be same. This holds good for any medium.
a
See lessExplanation: The normal component and tangential components of the magnetic flux
density will be same. This holds good for any medium.
The flux density of medium 1 has a normal component of 2.4 units, then the normal component of the flux density in the medium 2 will be
c Explanation: Unlike the electric fields, the magnetic flux density has normal component same in both the mediums. This gives Bn1 = Bn2.
c
See lessExplanation: Unlike the electric fields, the magnetic flux density has normal component same in both the mediums. This gives Bn1 = Bn2.