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In air, the tangential component of flux density is continuous at the boundary. State True/False.
a Explanation: Since the tangential component of the magnetic field intensity will be continuous and B = μH, in air, the tangential component of the flux density will also be continuous.
a
See lessExplanation: Since the tangential component of the magnetic field intensity will be
continuous and B = μH, in air, the tangential component of the flux density will also be continuous.
The tangential component of the magnetic field intensity is continuous at the boundary of separation of two media. State True/False.
a Explanation: For two medium of separation, the tangential component of the magneticfield intensity will be continuous. This is analogous to the fact that the tangential component of the electric field intensity is continuous at the boundary.
a
See lessExplanation: For two medium of separation, the tangential component of the magneticfield intensity will be continuous. This is analogous to the fact that the tangential component of the electric field intensity is continuous at the boundary.
Find the correct relation between current density and magnetization.
c Explanation: The curl of the magnetization gives the magnetic field intensity theoretically. From Maxwell equation, we can correlate that with the current density (Ampere law)
c
See lessExplanation: The curl of the magnetization gives the magnetic field intensity
theoretically. From Maxwell equation, we can correlate that with the current density
(Ampere law)
Identify the diamagnetic material.
b Explanation: The diamagnetic materials are characterised by very small or negative susceptibility. Also the susceptibility is independent of the temperature. The material having these properties is germanium from the given options. Metals like gold and atoms with closed shells are also diamagneticRead more
b
See lessExplanation: The diamagnetic materials are characterised by very small or negative
susceptibility. Also the susceptibility is independent of the temperature. The material
having these properties is germanium from the given options. Metals like gold and atoms with closed shells are also diamagnetic.
Which of the following materials is ferrimagnetic?
c Explanation: Fe is iron and a ferromagnetic material. Sn and FeCl are not magnetic materials. The oxides of iron like ferric oxide Fe2O3 is said to be a ferrimagnetic material.
c
See lessExplanation: Fe is iron and a ferromagnetic material. Sn and FeCl are not magnetic
materials. The oxides of iron like ferric oxide Fe2O3 is said to be a ferrimagnetic material.
Calculate the magnetization of a material with susceptibility of 50 and field intensity of 0.25 units.
a Explanation: The magnetization is the product of the susceptibility and the field intensity given by M = χmH. Put χm = 50 and H = 0.25, then M = 50 x 0.25 = 12.5 units.
a
See lessExplanation: The magnetization is the product of the susceptibility and the field intensity given by M = χmH. Put χm = 50 and H = 0.25, then M = 50 x 0.25 = 12.5 units.
Find the permeability of a medium whose susceptibility is 100.
d Explanation: The susceptibility is given by χm = μr-1. To get permeability, μr = χm + 1 = 100 + 1 = 101 units.
d
See lessExplanation: The susceptibility is given by χm = μr-1. To get permeability, μr = χm + 1 = 100 + 1 = 101 units.
The expression for magnetization is given by(I-current, A-area, V-volume)
b Explanation: The magnetization is defined as the magnetic moment per unit volume and the magnetic moment is IA. Thus M = IA/V is the expression.
b
See lessExplanation: The magnetization is defined as the magnetic moment per unit volume and the magnetic moment is IA. Thus M = IA/V is the expression.
Find the current in a dipole with a moment of 16 units and area of 9 units.
a Explanation: The dipole moment is given by M = IA. To get I, put M = 16 and A = 9, we get I = M/A = 16/9 = 1.78 units.
a
See lessExplanation: The dipole moment is given by M = IA. To get I, put M = 16 and A = 9, we get I = M/A = 16/9 = 1.78 units.
The torque expression of a current carrying conductor is
c Explanation: The torque is given by the product of the flux density, magnetic moment IA and the sine angle of the conductor held by the field. This gives T = BIA sin θ.
c
See lessExplanation: The torque is given by the product of the flux density, magnetic moment IA and the sine angle of the conductor held by the field. This gives T = BIA sin θ.